package com.ming.learn.from.carl.doublepointer;

/*
题目：344. 反转字符串
 */
public class Of20201228LeetCode344 {
    /*
    编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。
    不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
    你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。
    示例 1：
    输入：["h","e","l","l","o"] 输出：["o","l","l","e","h"] 示例 2：
    输入：["H","a","n","n","a","h"] 输出：["h","a","n","n","a","H"]
     */
    public static void main(String[] args) {
        char[] s = "a,b,c,d,e".toCharArray();
        reverseString(s);
        System.out.println(new String(s));
    }

    private static void reverseString(char[] s) {
        for (int i = 0, j = s.length-1; i < j; i++, j--) {
            s[i] ^= s[j];
            s[j] ^= s[i];
            s[i] ^= s[j];
        }
    }
}
